Logarithms and Exponents: Laws, Formulas, Log Values and Solved Examples for SSC CGL and CHSL Maths
Rahul Kumar
SSC Exam Expert & Content Editor
In this note
- 1.Laws of Exponents (Indices)
- 2.Definition of Logarithm
- 3.Laws of Logarithms
- 4.Standard Values (Base 10)
- 5.Number of Digits Using Logs
- 6.Solved Examples
- 7.Common Question Types
- 8.Tricks
- 9.Quick Tips
- 10.Quick Revision Points
- 11.Practice Questions With Answers
- 12.How to Practise This Chapter
- 13.Frequently Asked Questions
PDF Notes: Logarithms and Exponents: Laws, Formulas, Log Values and Solved Examples for SSC CGL and CHSL Maths
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Exponents (indices) and logarithms are closely related, and questions on them in SSC CGL and CHSL are based on a small set of laws. This guide on logarithms and exponents for SSC covers the laws of indices, the laws of logs, standard log values, finding the number of digits and the usual question types, with solved examples, tricks and practice questions.
Laws of Exponents (Indices)
| Law | Formula |
|---|---|
| Product | a^m × a^n = a^(m + n) |
| Quotient | a^m / a^n = a^(m − n) |
| Power of a power | (a^m)^n = a^(mn) |
| Power of a product | (ab)^n = a^n × b^n |
| Zero power | a^0 = 1 |
| Negative power | a^(−n) = 1 / a^n |
| Fractional power | a^(m/n) = nth root of (a^m) |
Definition of Logarithm
If a^x = N, then x = loga N. For example, 2³ = 8, so log2 8 = 3. The base a must be positive and not equal to 1, and N must be positive.
Laws of Logarithms
| Law | Formula |
|---|---|
| Product | log(mn) = log m + log n |
| Quotient | log(m/n) = log m − log n |
| Power | log(m^n) = n log m |
| Same base | log_a a = 1 |
| Log of one | log_a 1 = 0 |
| Change of base | log_a b = log b / log a |
| Reciprocal | log_a b = 1 / log_b a |
| Base power | a^(log_a N) = N |
Standard Values (Base 10)
| Number | log10 |
|---|---|
| 2 | 0.3010 |
| 3 | 0.4771 |
| 5 | 0.6990 (= 1 − 0.3010) |
| 7 | 0.8451 |
| 10 | 1 |
| 100 | 2 |
Number of Digits Using Logs
If log10 N = x, then the number of digits in N = (integer part of x) + 1. For example, 2^20: 20 × 0.3010 = 6.02, so there are 7 digits. 3^10: 10 × 0.4771 = 4.771, so there are 5 digits (3^10 = 59,049).
Solved Examples
Example 1. Find log2 64.
64 = 2^6, so the value is 6.
Example 2. Find log 5 + log 20 (base 10).
log(5 × 20) = log 100 = 2.
Example 3. Find log3 81 − log3 9.
4 − 2 = 2.
Example 4. If log 2 = 0.3010, find log 8 and log 5.
log 8 = 3 × 0.3010 = 0.9030. log 5 = log(10/2) = 1 − 0.3010 = 0.6990.
Example 5. Solve log2 x = 5.
x = 2^5 = 32.
Example 6. Find x if logx 625 = 4.
x^4 = 625 = 5^4, so x = 5.
Example 7. Solve 2^(x + 1) = 32.
32 = 2^5, so x + 1 = 5 and x = 4.
Example 8. Solve 9^x = 27.
3^(2x) = 3^3, so 2x = 3 and x = 1.5.
Example 9. Simplify (2^5 × 2^3) / 2^6.
2^(5 + 3 − 6) = 2^2 = 4.
Common Question Types
| Type | Method |
|---|---|
| Find the value of a log | Write the number as a power of the base |
| Solve for x | Convert the log form to the index form |
| Simplify using laws | Combine logs with product, quotient and power laws |
| Number of digits | Use log10 N and add 1 to the integer part |
| Equal bases in equations | Make the bases equal and equate the powers |
Tricks
- Learn powers of 2, 3, 5 and 7 up to at least 2^10, 3^6, 5^4 and 7^3.
- Make the bases equal in index equations.
- Remember that log of a number less than 1 is negative.
- Use the change of base formula when bases differ.
- log 1 = 0 and log_a a = 1 in any base.
Quick Tips
- Write the number as a power of the base to find the log.
- Make bases equal in index equations.
- Learn log 2 = 0.3010 and log 3 = 0.4771.
- For the number of digits, add 1 to the integer part of the log.
Quick Revision Points
- a^m × a^n = a^(m + n); (a^m)^n = a^(mn).
- a^0 = 1 and a^(−n) = 1/a^n.
- log(mn) = log m + log n; log(m/n) = log m − log n.
- log(m^n) = n log m.
- Digits in N = integer part of log10 N + 1.
Practice Questions With Answers
- Find log3 243.
Answer: 5 - Find log 4 + log 25 (base 10).
Answer: 2 - Solve 3^x = 81.
Answer: 4 - If log 2 = 0.3010, find log 16.
Answer: 1.2040 - Find log5 125.
Answer: 3 - Solve 4^x = 8.
Answer: 1.5 - Find the number of digits in 2^30 (log 2 = 0.3010).
Answer: 10 - Find log2 (1/8).
Answer: −3 - Simplify (3^4 × 3^2) / 3^3.
Answer: 27 - Find x if logx 64 = 3.
Answer: 4
How to Practise This Chapter
Practise 10 questions every day and write the steps on paper. Then attempt timed sets from our practice papers and the previous year papers page. See all topics on the Quantitative Aptitude notes page, read the previous topic Chain Rule and Variation and the next topic Set Theory and Venn Diagram.
Frequently Asked Questions
What is a logarithm?
If a^x = N, then x is the logarithm of N to the base a, written log_a N.
What is the product law of logarithms?
log(mn) = log m + log n.
What is the quotient law of logarithms?
log(m/n) = log m − log n.
What is the power law of logarithms?
log(m^n) = n times log m.
What is the value of log 1?
It is 0 in any base.
What is log_a a?
It is always 1.
What is the value of log 2 in base 10?
About 0.3010.
How do I find the number of digits of a number using logs?
Find log10 of the number, take the integer part and add 1.
What is the change of base formula?
log_a b = log b / log a.
Can I take the log of a negative number?
No. The log is defined only for positive numbers.
What is a^0?
It is 1 for any non-zero a.
Are logs asked in SSC CGL?
Yes. 1 or 2 questions on logs and indices appear in Tier I and Tier II.
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Chain Rule and Direct and Inverse Variation: Formulas, Tricks and Solved Examples for SSC CGL, CHSL and MTS
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Set Theory and Venn Diagram Maths: Formulas, Two and Three Set Problems with Solved Examples for SSC
Rahul Kumar
SSC Exam Expert & Content Editor
Rahul is a senior SSC exam strategist with 8+ years of experience helping aspirants crack CGL, CHSL and MTS exams. He writes in-depth notification breakdowns, exam pattern guides and preparation strategies.